Forgive my delayed answer. The last paragraph is the content-rich one. You say “If the body is stopped below, it loses some of its energy, namely kinetic energy, but its mass stays the same of course.”

I agree. And I ask you to contradict me if I here adduce again the example of the idealized neutron star with z = 1 (that is, a halving of the local speed of time). In this case the kinetic energy set free on landing just suffices to build a second stone of the same local weight. Do you agree?

Thank you.

This would be a good advice if I was talking to a rational person, but so far you have not shown the slightest reluctance to dispute even the most obvious facts, or assume contradictory statements about these facts.

It starts with your description of Birkhoff’s theorem which is just absurdly wrong (Birkhoff didn’t show that gravitational mass is invariant. He did show that a particular vacuum solution, namely the Schwarzschild metric, is unique under certain conditions.) But fortunately, for once, your confusion doesn’t matter since Birkhoff’s theorem is completely unrelated to this discussion. I don’t know why you keep bringing it up.

“Then imagine a lower-level observer. The same mass-carrying body can be arrested on his floor as it were. To him, the rest mass — the mass he can measure on this body that is now at rest relative to him — is unchaged compared to what the higher-up observer measured when the same massive body was at rest relative to him. I think you will not disagree.
But then we have a problem, right?”

Well, I don’t.

“The body having come to rest relative to the lower-level observer no longer has the full “total mass” (“mass-energy”?) it possessed up there. For part of that mass (or energy) was dissipated when the mass was arrested down there. We even had the example of z=1 when the two local masses, that of the body come to rest itself and that of its re-collected kinetic energy, were both equal.

You did not bear with me on that previous occasion because you did not reply. Can you do so now? Specifically: Can you re-formulate the problem into a technical language you understand and can stick to, so that I can try and understand what you mean in that language?”

Yes I did. The problem is your confusion of two terms of that “technical language” namely, “energy” and “mass.” You were just successfully demonstrating this by blithely interchanging them again in the preceding paragraph. Mass doesn’t get dissipated during the process you described. If the body is stopped below, it loses some of its energy, namely kinetic energy, but its mass stays the same of course. I already explained the difference to you and why it matters to your argument. Maybe you should go back reading what I wrote.

Without changing or introducing new examples of your confusion, there is no reason for that unless you have resolved the problems with the older statements.

BTW, as a proven liar you are the last person who should accuse others with someting like disinformation.

Can you say a word to the angular-momentum proof of Telemach given yesterday?

I repeat it in even clearer terms here:

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“Angular-momentum Conservation Confirms Telemach“

Otto E. Rossler, University of Tubingen, Auf der Morgenstelle 14, D-72076 Tübingen, F.R.G.

Friction-free clocks (rotating wheels) that are transported towards a lower level in gravity (or in the equivalence principle) rotate more slowly down there in accord with Einstein’s gravitational clock slowdown (“gravitational twin paradox”). They therefore must also be enlarged down there in order to conserve their angular momentum J.

To witness, take an ideal bicycle wheel with

J = m * r^2 * omega = const., (1)

where m denotes the wheel’s mass, r its radius and omega its rotation rate.

The 3 predictions made by Telemach [1] hold true on an idealized neutron star (with a unit redshift valid on its surface). Down there on the neutron star’s surface, m is halved, r doubled and omega halved. Thus, J is exactly conserved!

This is a test which any correct interpretation of general relativity (and the Rindler metric) must pass. The currently favored interpretations flunk this test. Therefore they are in for an overhaul. Telemach points the way.

I thank Heinrich Kuypers for his cooperation. (For J.O.R.)

References

[1] O.E. Rossler, Einstein’s equivalence principle has three further implications besides affecting time: T-L-M-Ch theorem (“Telemach”), African Journal of Mathematics and Computer Science Research 5, 44 — 47 (2012). http://www.scribd.com/doc/82752272/Rossler-s-Telemach-paper

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